Find a cubic polynomial whose zeros are 2, –3 and 4
Let the zeros of the polynomial be a, b and c
Where a = 2, b = - 3 and c = 4
The cubic polynomial can be calculated as follows:
x3 – (a + b + c) x2 + (ab + bc + ca)x – abc
Putting the values of a, b and c in the above equation we get:
= x3 – (2 – 3 + 4) x2 + (-6 – 12 + 8) x – (- 24)
= x3 – 3x2 – 10x + 24