If 1 is a zero of the polynomial ax^{2} ‒ 3 (a ‒ 1) x ‒ 1 then find the value of a.

It is given in the question that,

One of the zero of the polynomial ax^{2} – 3 (a – 1) x - 1 is 1

∴ It will satisfy the above polynomial

Now, we have

a (1)^{2} – (a – 1) 1 – 1 = 0

a – 3a + 3 - 1 = 0

- 2a = - 2

5k = - 6

∴ a = 1

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