The zeros of the polynomial x2 ‒ √2 x – 12 are
We have, f(x) = x2 ‒ 
x – 12
Now, put f(x) = 0
x2 ‒ 
x – 12 = 0
x(x ‒ 3√2) + 2√2 x – 3√2)=0
(x ‒ 3√2) + (x + 2√2) = 0
Thus, x= 3√2 , -2√2
Hence option B is correct.
4
The zeros of the polynomial x2 ‒ √2 x – 12 are
We have, f(x) = x2 ‒ x – 12
Now, put f(x) = 0
x2 ‒ x – 12 = 0
x(x ‒ 3√2) + 2√2 x – 3√2)=0
(x ‒ 3√2) + (x + 2√2) = 0
Thus, x= 3√2 , -2√2
Hence option B is correct.