The zeros of the polynomial are
f(x) = 21x2 – 11x – 2 =0
Now, put f(x) = 0
21x2 – 11x – 2 =0
21x2 – 14x + 3x – 2 =0
7x(3x – 2) + 1 (3x – 2) = 0
(3x – 2) (7x + 1) = 0
Hence, option A is correct.