If one zero of the quadratic polynomial (k – 1) x^{2} + kx + 1 is –4 then the value of k is

Given: -4 is the zero of the polynomial f(x) = (k – 1) x^{2} + kx + 1

Put f(-4) = 0

(k – 1)(-4)^{2} + k(-4) + 1 = 0

16k -16 – 4k + 1 = 0

Hence, option B is correct.

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