If one zero of the quadratic polynomial (k – 1) x2 + kx + 1 is –4 then the value of k is
Given: -4 is the zero of the polynomial f(x) = (k – 1) x2 + kx + 1
Put f(-4) = 0
(k – 1)(-4)2 + k(-4) + 1 = 0
16k -16 – 4k + 1 = 0
Hence, option B is correct.
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