If –2 and 3 are the zeros of the quadratic polynomial x2 + (a + 1) x + b then

It is given in the question that, -2 and 3 are the zeros of x2 + (a + 1) x + b


(- 2)2 + (a + 1) × (- 2) + b = 0


4 – 2a – 2 + b = 0


b – 2a = - 2 (i)


Also, we have


32 + (a + 1) × 3 + b = 0


9 + 3a + 3 + b = 0


b + 3a = - 12 (ii)


Now, by subtracting the equation (i) from (ii) we get:


a = - 2


Also, b = - 2 – 4 = - 6

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