If one of the zeros of the cubic polynomial x3 + ax2 + bx + c is –1 then the product of the other two zeros is
It is given in the question that,
- 1 is the zero of the given polynomial x3 + ax2 + bx + c
∴ (- 1)3 + a × (- 1)2 + b × (- 1) + c = 0
a – b + c + 1 = 0
c = 1 – a + b
Also, the product of all zeros is:
× (- 1) = - c
= c
= 1 – a + b
Hence, option C is correct
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