Zeros of p(x) = x2 – 2x – 3 are

It is given in the question that,

p (x) = x2 – 2x – 3


Let us assume x2 – 2x – 3 = 0


x2 – (3 – 1) x - 3 = 0


x2 – 3x + x – 3 = 0


x (x – 3) + 1 (x – 3) = 0


(x – 3) (x + 1) = 0


x = 3, - 1

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