Zeros of p(x) = x2 – 2x – 3 are
It is given in the question that,
p (x) = x2 – 2x – 3
Let us assume x2 – 2x – 3 = 0
x2 – (3 – 1) x - 3 = 0
x2 – 3x + x – 3 = 0
x (x – 3) + 1 (x – 3) = 0
(x – 3) (x + 1) = 0
x = 3, - 1