If is given that the difference between the zeros of 4x2 – 8kx + 9 is 4 and k > 0. Then k = ?

Let us assume the zeros of the polynomial be

We have,


p (x) = 4x2 – 8kx + 9


Now comparing the given polynomial with ax2 + bx + c, we get:


a = 4, b = - 8kx + 9


Sum of roots =


=


2 + 4 = 2k


+ 2 = k


= (k – 2) (i)


, we have product of roots, =


+ 4) =


(k – 2) (k – 2 + 4) =


(k – 2) (k + 2) =


k2 – 4 =


4k2 – 16 = 9


4k2 = 25


k2 =


k =


k =

5