Show that (x + 2) is a factor of f(x) = x3 + 4x2 + x – 6.
It is given in the question that,
f (x) = x3 + 4x2 + x – 6
Now, we have
f (- 2) = (- 2)3 + 4 (- 2)2 + (- 2) - 6
= - 8 + 16 – 2 - 6
= 0
Hence, (x + 2) is a factor of f (x)