Show that each of the progressions given below is an AP. Find the first term, common difference and next term of each.
9, 15, 21, 27, ...
Here, T2 - T1 = 15 - 9 = 6
T3 - T2 = 21 - 15 = 6
T4 - T3 = 27 - 21 = 6
Since the difference between each consecutive term is same, ∴ the progression is an AP.
So, first term = 9
Common difference = 15 - 9 = 6
Next term = T5 = T4 + d = 27 + 6 = 33