Write the molecular formula of the third member of the homologues series of carbon compounds with general formula CnH2n+1OH.
The general formula of homologous series of alcohol is CnH2n+1 -OH. Here, n is the number of carbon atoms in alcohol molecule.

If number of carbon atom (n)=3


Then, C3H2X3+1 OH= C3H7OH


Thus, the molecular formula of the third member of the homologues series of alcohol is C3H7OH. The IUPAC name of C3H7OH is propanol.


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