In the given AP, the first term = a = 5/6

Common difference = d = 1 - 5/6 = 1/6

To find: place of the term 3.

So, let a_n = 3

Since, we know that

a_n = a + (n - 1) × d

∴ 3 = (5/6) + (n - 1) × (1/6)

⇒ 3 - (5/6) = (n - 1) × (1/6)

⇒ 13/6 = (n - 1) × (1/6)

⇒ 13 = n - 1

⇒ n = 13 + 1

⇒ n = 14

∴ 14^th term of the AP is 3.