Let a be the first term and d be the common difference.

Given: a₇ = - 1

a₁₆ = 17

Now, Consider a₇ = - 1

⇒ a + (7 - 1)d = - 1

⇒ a + 6d = - 1 ……….(1)

Consider a₁₆ = 17

⇒ a + (16 - 1)d = 17

⇒ a + 15d = 17 ……….(2)

Now, subtracting equation (1) from (2), we get,

9d = 18

⇒ d = 2

∴ from equation (1), we get,

a = - 1 - 6d

⇒ a = - 1 - 6 × (2)

⇒ a = - 1 - 12

⇒ a = - 13

Now, the n^th term of the AP is given by:

a_n = a + (n - 1)d

∴ a_n = - 13 + (n - 1) × 2

⇒ a_n = 2n - 15

∴ n^th term of the AP is (2n - 15)