Determine k so that (3k - 2), (4k - 6) and (k + 2) are three consecutive terms of an AP.

Question

Philoid · Accepted Answer

Since, the terms are in an AP, therefore

(4k - 6) - (3k - 2) = (k + 2) - (4k - 6)

⇒ k - 4 = - 3k + 8

⇒ 4k = 12

⇒ k = 3

∴ k = 3