Find the value of x for which the numbers (5x + 2), (4x - 1) and (x + 2) are in AP.
Since, the terms are in an AP, therefore
(4x - 1) - (5x + 2) = (x + 2) - (4x - 1)
⇒ - x - 3 = - 3x + 3
⇒ 2x = 6
⇒ x = 3
∴ x = 3