If the numbers (2n – 1), (3n + 2) and (6n – 1) are in AP, find the value of n and the numbers.

Question

Philoid · Accepted Answer

Since, the terms are in an AP, therefore

(3n + 2) - (2n - 1) = (6n - 1) - (3n + 2)

⇒ n + 3 = 3n - 3

⇒ 2n = 6

⇒ n = 3

∴ n= 3, and hence the numbers are 5, 11, 17.