The 5th term of an AP is 20 and the sum of its 7th and 11th terms is 64. The common difference of the AP is
Let a be the first term and d be the common difference.
Given: a5 = 20
a7 + a11 = 64
Now, Consider a5 = 20
⇒ a + 4d = 20 ……………(1)
Consider a7 + a11 = 64
⇒ a + 6d + a + 10d = 64
⇒ 2a + 16d = 64 …………(2)
Subtract twice of equation (1) from (2), we get,
8d = 24
⇒ d = 3