An AP 5, 12, 19, ... has 50 terms. Its last term is
Here, first term = 5
Common difference = 12 - 5 = 7
Given that there are 50 terms in the AP.
To find: Last term, i.e. 50th term = a50
Since an = a + (n - 1)d
∴ a50 = 5 + (50 - 1)7
= 5 + (49) × 7
= 5 + 343
= 348