Find the mean of the following frequency distribution using a suitable method:
Class | 20 - 30 | 30 - 40 | 40 - 50 | 50 - 60 | 60 - 70 |
Frequency | 25 | 40 | 42 | 33 | 10 |
We will find the mean of the frequency distribution using step - deviation method, where A = Assumed mean and h = length of class interval.
Here, let A = 45 and h = 10
CLASS | MID - POINT(xi) | DEVIATION(di) di = xi – 45 | FREQUENCY(fi) | ui = di/h | fiui |
20 - 30 | 25 | - 20 | 25 | - 2 | - 50 |
30 - 40 | 35 | - 10 | 40 | - 1 | - 40 |
40 - 50 | 45 = A | 0 | 42 | 0 | 0 |
50 - 60 | 55 | 10 | 33 | 1 | 33 |
60 - 70 | 65 | 20 | 10 | 2 | 20 |
TOTAL | 150 | - 37 |
We have got
A = 45, h = 10, Σfi = 150 & Σfiui = - 37
∵ mean is given by
⇒
⇒
Thus, mean is 42.53.