Heights of students of Class X are given in the following frequency distribution:


Height (in cm)



150 - 155



155 - 160



160 - 165



165 - 170



170 - 175



Number of students



15



8



20



12



5



Find the modal height.


Also, find the mean height. Compare and interpret the two measures of central tendency.

Here, the maximum class frequency is 20.

The class corresponding to this frequency is the modal class. modal class = 160 - 165


lower limit of the modal class (l) = 160


Modal class size (h) = 5


Frequency of the modal class (f1) = 20


Frequency of class preceding the modal class (f0) = 8


Frequency of class succeeding the modal (f2) = 12


Mode is given by,





Mode = 160 + 3 = 163


Hence, the mode is 163 cm.


Mode represents frequency, hence 163 cm is the height of maximum number of students.


To find the mean, we will solve by using direct method.


HEIGHT (cm)



MID - POINT(xi)



NUMBER OF STUDENTS(fi)



fixi



150 - 155



152.5



15



2287.5



155 - 160



157.5



8



1260



160 - 165



162.5



20



3250



165 - 170



167.5



12



2010



170 - 175



172.5



5



862.5



TOTAL




60



9670



We have got


Σfi = 60 & Σfixi = 9670


mean is given by





Thus, mean is 161.17


Mean represents average, thus 161.7 cm is the average height of all the students.


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