It is known that a box of 200 electric bulbs contains 16 defective bulbs. One bulb is taken out at random from the box. What is probability that the bulb drawn is (i) defective, (ii) non-defective?

(i) Total numbers of bulbs are: 200

Let E be the event of drawing defective bulb


Then, the numbers of favourable outcomes are= 16


P (drawing defective bulb) = P (E) = 16/200= 2/25


(ii) Total numbers of bulbs are: 200


Let E be the event of drawing non defective bulb


Then, the numbers of favourable outcomes are: 200 -16 =184 non defective bulbs out of which one can be chosen in 184 ways


P (drawing non defective bulb) = P (E) = 184/200 = 23/25 or 92%


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