Two difference dice are rolled simultaneously. Find the probability that the sum of the numbers on the two dice is 10.
Total numbers of elementary events are: 6 x6 = 36
Let E be the event of getting the sum of the numbers on the two dice is 10
The favourable combination is: (5, 5), (4, 6), (6, 4)
The numbers of favourable combinations are: 3
∴ P (getting sum of numbers on the dice is 10) = P (E) = 3/36 = 1/12