Two dice are thrown together. The probability of getting a doublet is
Total numbers of elementary events are: 6 x 6 = 36
Let E be the event of getting a doublet
Favourable outcomes are: (1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6)
Number of favourable outcomes = 6
P (E) = 6/36 =1/6