We have,

x – y = 3 …eq.1

…eq.2

Let us first simplify eq.2, by taking LCM of denominator,

⇒

⇒ 2x + 3y = 36 …eq.3

To solve these equations, we need to make one of the variables (in both the equations) have same coefficient.

Lets, multiply eq.1 by 2, so that variable x in both the equations have same coefficient.

Recalling equations 1 & 2,

x – y = 3 [×2

2x + 3y = 36

⇒ 2x – 2y = 6

2x + 3y = 36

On solving we get,

⇒ - 5y = - 30

⇒ y = 6

Substitute y = 6 in eq.1/eq.3, as per convenience of solving.

Thus, substituting in eq.1, we get

x – (6) = 3

⇒ x = 3 + 6

⇒ x = 9

Hence, we have x = 9 and y = 6.