We have,

2x – 3y = 13 …eq.1

7x – 2y = 20 …eq.2

To solve these equations, we need to make one of the variables (in both the equations) have same coefficient.

Lets multiply eq.1 by 2 and eq.2 by 3, so that variable y in both the equations have same coefficient.

Recalling equations 1 & 2,

2x – 3y = 13 [×2]

7x – 2y = 20 [×3]

⇒ 4x – 6y = 26

21x – 6y = 60

On solving the two equations we get,

- 17x = - 34

⇒ x = 2

Substitute x = 2 in eq.1/eq.2, as per convenience of solving.

Thus, substituting in eq.1, we get

2(2) – 3y = 13

⇒ - 3y = 13 – 4

⇒ - 3y = 9

⇒ y = - 3

Hence, we have x = 2 and y = - 3.