Rearranging the equations, we have

3x – 5y = 19 …eq.1

- 7x + 3y = - 1 …eq.2

To solve these equations, we need to make one of the variables (in both the equations) have same coefficient.

Lets multiply eq.1 by 7 and eq.2 by 3, so that variable x in both the equations have same coefficient.

Recalling equations 1 & 2,

3x – 5y = 19 [×7

- 7x + 3y = - 1 [×3

⇒ - 26y = 130

⇒ y = - 5

Substitute y = - 5 in eq.1/eq.2, as per convenience of solving.

Thus, substituting in eq.2, we get

- 7x + 3( - 5) = 13

⇒ - 7x – 15 = - 1

⇒ - 7x = 15 – 1 = 14

⇒ x = - 2

Hence, we have x = - 2 and y = - 5.