Solve for x and y:

2x - y + 3 = 0, 3x - 7y + 10 = 0.

Rearranging the equations, we have

2x – y = - 3 …eq.1


3x – 7y = - 10 …eq.2


To solve these equations, we need to make one of the variables (in both the equations) have same coefficient.


Lets multiply eq.1 by 7, so that variable y in both the equations have same coefficient.


Recalling equations 1 & 2,


2x – y = - 3 [×7


3x – 7y = - 10


14x – 7y = - 21


3x – 7y = - 10


On solving the above two equations we get,


11x = - 11


x = - 1


Substitute x = - 1 in eq.1/eq.2, as per convenience of solving.


Thus, substituting in eq.1, we get


2( - 1) – y = - 3


- 2 – y = - 3


y = - 2 + 3


y = 1


Hence, we have x = - 1 and y = 1.


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