Solve for x and y:
4x - 3y = 8,
We have,
4x – 3y = 8 …eq.1
…eq.2
Let us first simplify eq.2 by taking LCM of denominator,
Eq.2 ⇒
⇒ 18x – 3y = 29 …eq.3
To solve these equations, we need to make one of the variables (in both the equations) have same coefficient.
And it is so that the equations 1 & 3 have variable y having same coefficient already, so we need not multiply or divide it with any number.
Recalling equations 1 & 3,
4x – 3y = 8
18x – 3y = 29
⇒ 4x – 3y = 8
18x – 3y = 29
On solving the above equations we get,
⇒ - 14x = - 21
⇒
⇒
Substitute in eq.1/eq.3, as per convenience of solving.
Thus, substituting in eq.1, we get
4 – 3y = 8
⇒ 6 – 3y = 8
⇒ 3y = 6 – 8
⇒ 3y = - 2
⇒
Hence, we have and