Solve for x and y:

2x + 3y + 1 = 0,

After rearrangement, we have

2x + 3y = - 1 …eq.1


…eq.2


Let us first simplify eq.2 by taking LCM of denominator,


Eq.1


7 – 4x = 3y


4x + 3y = 7 …eq.3


To solve these equations, we need to make one of the variables (in both the equations) have same coefficient.


And it is so that the equations 1 & 3 have variable y having same coefficient already, so we need not multiply or divide it with any number.


Recalling equations 1 & 3,


2x + 3y = - 1


4x + 3y = 7


On solving these two equations we get,


x = 4


Substitute x = 4 in eq.1/eq.3, as per convenience of solving.


Thus, substituting in eq.3, we get


4(4) + 3y = 7


16 + 3y = 7


3y = 7 – 16


3y = - 9


y = - 3


Hence, we have x = 4 and y = - 3


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