Solve each of the following systems of equations by using the method of cross multiplication:
6x – 5y – 16 = 0, 7x – 13y + 10 = 0.
We have,
6x – 5y – 16 = 0 …(i)
7x – 13y + 10 = 0 …(ii)
From equation (i), we get a1 = 6, b1 = - 5 and c1 = - 16
And from equation (ii), we get a2 = 7, b2 = - 13 and c2 = 10
Using cross multiplication,
⇒
⇒
⇒
⇒ and
⇒ and
⇒ x = 6 and y = 4
Thus, x = 6, y = 4