Solve each of the following systems of equations by using the method of cross multiplication:

2x + 5y = 1, 2x + 3y = 3

We have,

2x + 5y – 1 = 0 …(i)


2x + 3y – 3 = 0 …(ii)


From equation (i), we get a1 = 2, b1 = 5 and c1 = - 1


And from equation (ii), we get a2 = 2, b2 = 3 and c2 = - 3


Using cross multiplication,







and


and


x = 3 and y = - 1


Thus, x = 3, y = - 1


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