Solve each of the following systems of equations by using the method of cross multiplication:
2x + 5y = 1, 2x + 3y = 3
We have,
2x + 5y – 1 = 0 …(i)
2x + 3y – 3 = 0 …(ii)
From equation (i), we get a1 = 2, b1 = 5 and c1 = - 1
And from equation (ii), we get a2 = 2, b2 = 3 and c2 = - 3
Using cross multiplication,
⇒
⇒
⇒
⇒ and
⇒ and
⇒ x = 3 and y = - 1
Thus, x = 3, y = - 1