Solve each of the following systems of equations by using the method of cross multiplication:
2x + y = 35, 3x + 4y = 65.
We have,
2x + y – 35 = 0 …(i)
3x + 4y – 65 = 0 …(ii)
From equation (i), we get a1 = 2, b1 = 1 and c1 = - 35
And from equation (ii), we get a2 = 3, b2 = 4 and c2 = - 65
Using cross multiplication,
⇒
⇒
⇒
⇒ and
⇒ and
⇒ x = 15 and y = 5
Thus, x = 15, y = 5