Solve each of the following systems of equations by using the method of cross multiplication:

2x + y = 35, 3x + 4y = 65.

We have,

2x + y – 35 = 0 …(i)


3x + 4y – 65 = 0 …(ii)


From equation (i), we get a1 = 2, b1 = 1 and c1 = - 35


And from equation (ii), we get a2 = 3, b2 = 4 and c2 = - 65


Using cross multiplication,







and


and


x = 15 and y = 5


Thus, x = 15, y = 5


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