Solve each of the following systems of equations by using the method of cross multiplication:

7x – 2y = 3, 22x – 3y = 16.

We have,

7x – 2y – 3 = 0 …(i)


22x – 3y – 16 = 0 …(ii)


From equation (i), we get a1 = 7, b1 = - 2 and c1 = - 3


And from equation (ii), we get a2 = 22, b2 = - 3 and c2 = - 16


Using cross multiplication,







and


and


x = 1 and y = 2


Thus, x = 1, y = 2


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