Solve each of the following systems of equations by using the method of cross multiplication:

Where x ≠ 0 and y ≠ 0

We have,

…(i)


…(ii)


Let 1/x = p and 1/y = q. Now,


From equation (i), ap – bq = 0


ap – bq + 0 = 0 …(iii)


From equation (ii), ab2p – a2bq = (a2 + b2)


ab2p – a2bq – (a2 + b2) = 0 …(iv)


From equation (iii), we get a1 = a, b1 = - b and c1 = 0


And from equation (iv), we get a2 = ab2, b2 = - a2b and c2 = - (a2 + b2)


Using cross multiplication,







and


and


p = 1/a and q = 1/b


Thus, x = a, y = b [ p = 1/x and q = 1/y]


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