Given: 2x – 3y = 17 – eq 1

4x + y = 13 – eq 2

Here,

a₁ = 2, b₁ = - 3, c₁ = 17

a₂ = 4, b₂ = 1, c₂ = 13

= , =

Here, ≠

∴ Given system of equations have unique solutions.

Now,

In – eq 1

2x = 17 + 3y

X =

Substitute x in – eq 2

we get,

4× + y = 13

= 13

68 + 12y + 2y = 26

68 + 14y = 26

14y = 26 – 68

14y = - 42

y = = - 3

∴ y = - 3

Now, substitute y in – eq 1

We get,

2x – 3×( - 3) = 17

2x + 9 = 17

2x = 17 – 9

2x = 8

x = 8/2 = 4

∴ x = 4

∴ x = 4 and y = - 3