Given: ⇒ 2x + 3y = 18 – eq 1

x - 2y = 2 – eq 2

Here,

a₁ = 2, b₁ = 3, c₁ = 18

a₂ = 1, b₂ = - 2, c₂ = 2

= , =

Here, ≠

∴ Given system of equations have unique solutions.

Now,

In – eq 1

2x = 18 – 3y

X =

Substitute x in – eq 2

we get,

– 2y = 2

= 2

18 – 3y – 4y = 4

18 – 7y = 4

7y = 18 – 4

7y = 14

y = = 2

∴ y = 2

Now, substitute y in – eq 1

We get,

x – 2×(2) = 2

x – 4 = 2

x = 2 + 4

x = 6

∴ x = 6

∴ x = 6 and y = 2