Find the value of k for which each of the following systems of equations has a unique solution:

4x + ky + 8 = 0, x + y + 1 = 0.

Given: 4x + ky + 8 = 0 – eq 1


x + y + 1 = 0 – eq 2


Here,


a1 = 4, b1 = k, c1 = 8


a2 = 1, b2 = 1, c2 = 1


Given systems of equations has a unique solution




4 ≠ k


k ≠ 4


4