Find the value of k for which each of the following systems of equations has a unique solution:
4x + ky + 8 = 0, x + y + 1 = 0.
Given: 4x + ky + 8 = 0 – eq 1
x + y + 1 = 0 – eq 2
Here,
a1 = 4, b1 = k, c1 = 8
a2 = 1, b2 = 1, c2 = 1
Given systems of equations has a unique solution
∴
≠
4 ≠ k
∴ k ≠ 4