A lady has only 25 - paisa and 50 - paisa coins in her purse. If she has 50 coins in all totalling Rs.19.50, how many coins of each kind does she have?
Let the no. of 25 - paisa coins be x.
the no of 50 - paisa coins = 50 - x
[∵ the total no. of coins = 50]
According to question -
total money = Rs. 19.50 = 1950 paisa
∴ 25x + 50(50 - x) = 1950
⇒ 2500 - 25x = 1950
⇒ 25x = 550
∴ x = 22
Thus, the no of 25 - paisa coins = x = 22 and,
the no of 50 - paisa coins = 50 - x = 50 - 22 = 28.
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