Find two numbers such that the sum of thrice the first and the second is 142, and four times the first exceeds the second by 138.

Let the two numbers be x and y.


According to question -


3x + y = 142.....(1)


4x - y = 138.....(2)


Adding equations (1) and (2) , we get -


7x = 280


∴ x = 40


substituting the value of x in equation (2), we get -


y = 142 - 3x = 142 - 120 = 22


Thus, the numbers are 40 and 22.


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