A number consisting of two digits is seven times the sum of its digits. When 27 is subtracted from the number, the digits are reversed. Find the number.

Let the two - digit number be xy (i.e. 10x + y).


After reversing the digits of the number xy, the new number becomes yx (i.e. 10y + x).


According to question -


(10x + y) = 7(x + y)


3x = 6y


x = 2y.....(1)


and,


(10x + y) - 27 = (10y + x)


9x - 9y = 27


x - y = 3.....(2)


Substituting equation (1) into (2), we get -


y = 3


Substitute the value of y in equation (1), we get -


x = 6


Thus, the required number is 63.


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