A two - digit number is such that the product of its digits is 18. When 63 is subtracted from the number, the digits interchange their places. Find the number.

Let the two - digit number be xy (i.e. 10x + y).


After reversing the digits of the number xy, the new number becomes yx (i.e. 10y + x).


According to question -


xy = 18


x = 18/y.....(1)


and,


(10x + y) - 63 = (10y + x)


9x - 9y = 63


x - y = 7.....(2)


Substituting the value of x in equation (2), we get -



18 - y2 = 7y


y2 + 7y - 18 = 0


y2 + 9y - 2y - 18 = 0


y(y + 9) - 2(y + 9) = 0


(y + 9)(y - 2) = 0


y = 2


[y = - 9 is invalid because digits of a number cannot be negative.]


Substituting the value of y in equation (1), we get -


x = 9


Thus, the required number is 92.


17