The sum of a two - digit number and the number obtained by reversing the order of its digits is 121, and the two digits differ by 3. Find the number.

Let the two - digit number be xy (i.e. 10x + y).


 


After reversing the digits of the number xy, the new number becomes yx (i.e. 10y + x).


 


According to question -


 


(10x + y) + (10y + x) = 121


 


11x + 11y = 121


 


x + y = 11.....(1)


 


and,


 


x - y = 3 or y - x = 3


 


[as we don't know which digit is greater out of x and y]


 


x - y = ±3.....(2)


 


Adding Equation (1) and (2), we get -


 


2x = 14 or 8


 


x = 7 or 4


 


Case 1. when x = 7


 


y = 4 [from equation (1)]


 


Case 2. when x = 4


 


y = 7 [from equation (1)]


 


Thus, the possible numbers are 47 or 74.


 

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