Five years hence, a man's age will be three times the age of his son. Five years ago, the man was seven times as old as his son. Find their present ages.

Question

Philoid · Accepted Answer

Let the age of the man and his son be x and y years respectively.

According to question -

x + 5 = 3(y + 5)

⇒ x - 3y = 10.....(1)

and,

x - 5 = 7(y - 5)

⇒ x - 7y = - 30.....(2)

Subtracting Equation (2) from (1), we get -

y = 10

Substituting the value of y in equation (1), we get -

x = 40

Thus, Man's age = 40 years

son's age = 10 years