Two years ago, a man was five times as old as his son. Two years later, his age will be 8 more than three times the age of his son. Find their present ages.

Question

Philoid · Accepted Answer

Let the age of the man and his son be x and y years respectively.

According to question -

x - 2 = 5(y - 2)

x - 5y = - 8.....(1)

and,

x + 2 = 3(y + 2) + 8

⇒ x - 3y = 12.....(2)

Subtracting Equation (1) from (2), we get -

y = 10

Substituting the value of y in equation (1), we get -

x = 42

Thus, Man's age = 42 years

son's age = 10 years