A chemist has one solution containing 50% acid and a second one containing 25% acid. How much of each should be used to make 10 litres of a 40% acid solution?

Question

Philoid · Accepted Answer

Let the 50% solution used be x litres

Total volume of solution = 10 litres ( Given )

∴ 25% solution used = (10 - x) litres

Volume of acid in mixture = 40% of 10 litres = 4 litres

but, volume of acid in mixture = 50% of x + 25% of (10 - x)

⇒ x + 10 = 16

⇒ x = 6 litres

Thus, 50% solution = 6 litres and 25% solution = 4 litres.