In a ∆ ABC,

∠A + ∠B + ∠C = 180°

[∴ In any ∆ABC, the sum of all the angles is 180°]

⇒ x° + (3x - 2)° + y° = 180°

⇒ 4x° + y° = 182°.....(1)

and,

∠C - ∠B = 9° (Given)

⇒ - 3x° + y° = 7°.....(2)

Subtracting equation (2) from equation (1), we get -

7x° = 175°

⇒ x° = 25°

Substituting the value of x° in equation (2), we get -

y° = 82°

Thus, ∠A = 25°, ∠B = 73° , ∠C = 82°