Given that x = - y and y > 0

Let us verify all the options by substituting the value of x.

Option A: x²y > 0

⇒ ( - y)² (y) > 0

⇒ y²(y) > 0

⇒ y³ > 0

Since y > 0, y³ >0 satisfies.

Option B: x + y = 0

⇒ ( - y) + y = 0

0 = 0

LHS = RHS

Hence satisfies.

Option C: xy < 0

⇒ ( - y)(y) < 0

⇒ - y² < 0

Hence satisfies.

Option D:

⇒

⇒

Since y > 0, also 1/y > 0 but - 2/y <0

Hence, it is not satisfied.