Solve the system of equations x - 2y = 0, 3x + 4y = 20.
x = 4, y = 2
Given: x - 2y = 0 … (1)
3x + 4y = 20 …(2)
By elimination method,
Step 1: Multiply equation (1) by 3 and equation (2) by 1 to make the coefficients of x equal.
Then, we get the equations as:
3x – 6y = 0 … (3)
3x + 4y = 20 … (4)
Step 2: Subtract equation (4) from equation (3),
(3x – 3x) + (4y + 6y) = 20 – 0
⇒ 10y = 20
y = 2
Step 3: Substitute y value in (1),
x – 2(2) = 0
⇒ x = 4
The solution is x = 4, y = 2.