The given equations are 23x + 29y = 98, 29x + 23y = 110.

We know that the general form for a pair of linear equations in 2 variables x and y is a₁x + b₁y + c₁ = 0

and a₂x + b₂y + c₂ = 0.

Comparing with above equations,

we have a₁ = 23, b₁ = 29, c₁ = - 98; a₂ = 29, b₂ = 23, c₂ = - 110

We can solve by cross multiplication method using the formula

Substituting values in the formula, we get

⇒

⇒

⇒ and

⇒ x = 3 and y = 1

The solution is x = 3 and y = 1.